It is possible to toggle the visibility of an element, using the functions .hide(), .show() or .toggle().

How would you test if an element is visible or hidden?

26 upvote
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It's worth mentioning (even after all this time), that $(element).is(":visible") works for jQuery 1.4.4, but not for jQuery 1.3.2, under Internet Explorer 8. This can be tested using Tsvetomir Tsonev's helpful test snippet. Just remember to change the version of jQuery, to test under each one. – Reuben
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  flag
This is related although a different question: //allinonescript.com/questions/17425543/… – Mark Schultheiss

51 Answers 11

if ( $(element).css('display') == 'none' ){
    // element is hidden
}

Functions don't work with the visibility attribute.

110 upvote
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This only checks for the display property of a single element. The :visible attribute checks also the visibility of the parent elements. – chiborg
12 upvote
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This is the only solution that worked for me when testing with IE 8. – evanmcd
2 upvote
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This is not the solution to my problem but the method helped me identify a fix for checking against a property to my problem. – dchayka
14 upvote
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@chiborg Yes, but sometimes that's what you want and I had to learn the hard way how "clever" jQuery was... – Casey
7 upvote
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This does answer the question, being the question is about a single element and by using the hide(), show() and toggle() functions, however, as most have already said, we should use the :visible and :hidden pseudo-classes. – Jimmy Knoot
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This answer can be used when an element exists but is not currently on the page, such as after detach(). – atheaos

You can use the hidden selector:

// Matches all elements that are hidden
$('element:hidden')

And the visible selector:

// Matches all elements that are visible
$('element:visible')
51 upvote
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just be careful, there are some good performance related tips in this presentation: addyosmani.com/jqprovenperformance – codecraig
16 upvote
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On pages 21 to 28 it shows how slow :hidden or :visible is compared to other selectors. Thanks for pointing this. – Etienne Dupuis
77 upvote
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When you're dealing with a couple of elements and very little is going on - i.e. THE ABSURDLY VAST MAJORITY OF CASES - the time issue is a ridiculously minor concern. Oh, noes! It took 42 ms instead of 19 ms!!! – vbullinger
9 upvote
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I am toggling the element mamually using this selector. $('element:hidden') is always true for me! – ZoomIn
1 upvote
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Could you explain why this one isn't working: jsfiddle.net/URHkb ? – Wolfpack'08
1 upvote
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:hidden is for form elements, not display:none. This is not the answer people are most likely expecting. – cwingrav
8 upvote
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@cwingrav You might want to re-read the documentation, :hidden applies to all elements. Form elements with type="hidden" is just one case that can trigger :hidden. Elements with no height and width, elements with display: none, and elements with hidden ancestors will also qualify as :hidden. – Joshua Walsh
2 upvote
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The embedded presenation on the linked page no longer works, go to slideshare.net/AddyOsmani/jquery-proven-performance-tips-tri‌​cks instead. – chiborg
2 upvote
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@vbullinger 42ms is actually a bit longer than I would like to wait for the website to respond to my actions - that means around 3 frames of animation dropped/delayed only at 60 fps – Sebi
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@vbullinger any processing that takes more than 16ms starts dropping FPS. So yes, if it takes 42ms it can be a bad deal if you're interested in performance. – Alejandro Iglesias
up vote 7836 down vote accepted

Since the question refers to a single element, this code might be more suitable:

// Checks for display:[none|block], ignores visible:[true|false]
$(element).is(":visible"); 

Same as twernt's suggestion, but applied to a single element; and it matches the algorithm recommended in the jQuery FAQ

127 upvote
  flag
This solution would seem to encourage the confustion of visible=false and display:none; whereas Mote's solution clearly illistrates the coders intent to check the display:none; (via mention of hide and show which control display:none not visible=true) – kralco626
73 upvote
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That is correct, but :visible will also check if the parent elements are visible, as chiborg pointed out. – Tsvetomir Tsonev
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Tsvetomir, this doesn't work for IE7 - even when the elements are hidden it thinks that visible=true. Please correct your answer to avoid misleading people. visible and display are different properties and should be treated as such. Mote's answer is the correct one. – sarsnake
34 upvote
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You have a point - I'll make it clear that the code checks only for the display property. Given that the the original question is for show() and hide(), and they set display, my answer is correct. By the way it does work with IE7, here's a test snippet - jsfiddle.net/MWZss ; – Tsvetomir Tsonev
38 upvote
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I actually found that the reverse logic words better: !$('selector').is(':hidden'); for some reason. Worth a try. – Kzqai
10 upvote
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Here's a simple benchmark testing is() against regexp:jsperf.com/jquery-is-vs-regexp-for-css-visibility. Conclusion: if you're out for performance, use regexp over is() (since is() looks for all hidden nodes first before looking at the actual element). – Max Leske
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Tchalvak, you may feel something is right, but try to explain why. Double negation is confusing as opposed to simple statement, so $('selector').is(':shown'); is much clearer than !$('selector').is(':hidden'); – Lamy
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@TsvetomirTsonev, to check the parent's visibility, you can use $(element).parent().is(":visible"); I know this is bit old, but will useful for new search – Robin Michael Poothurai
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What does $(element).is(":visible") return, if the element is visible in terms of not having display:none or visibility:hidden, but the user scrolled down so he doesn't actually see it? Is there a simple way to check that? – Martin Thoma
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For other users wondering if this really does work in IE7, this might save you some time - it works, jquery 1.9.1: imgur.com/uKD4t8h – Chris Moschini
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@MaxLeske - I'm pretty sure it's a GIVEN! (most of the time) that when you pull out the regexp knife that you'll take a perf. hit. The extra checks will be nil compared to the overhead/processing of regexp. – Bill Ortell
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How do you do the inverse of this? – Sevenearths
1 upvote
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I found this informative when looking up about :visible and :hidden. Essentially, it looks at the offsetHeight and offsetWidth allowing it to provide the best coverage (eg. you might have a class which has display:none; as a property and it will correctly report whether it is visible) – Turnerj
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So, should we use .is(":invisible") for false? Or !$(element).is(":visible"), or just what? – Wolfpack'08
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@Wolfpack'08: I'm looking for a similar solution as well. So far I've been using $(element).css('display')=='none' to detect hidden elements. – Ameen
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@Kzqai Also, I believe this works: $(selector).is('not(:hidden)') – Izkata
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This doesn't work in the latest jquery. It's been deprecated. What's the best work around? (Why did they remove this...?) – carl
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@carl I don't see anything in the jQuery documentation about this being deprecated. I have also tested it with the latest jQuery and it does still work. Here: jsfiddle.net/F6atJ – BruceHill
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This doesn't seem to return false if the element has opacity:0; set, any work around? – Keir Simmons
1 upvote
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Not working for element that have parent overflow: hidden; – Yana
1 upvote
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Does not work on chrome though works flawlessly in firefox :( Had to do something like jQuery(textarea).parent().css('display') != 'none' instead of jQuery(textarea).parent().is(":visible") – Aniket Thakur
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This doesn't work if it is hidden by a media query, how would I test for that? – SuperUberDuper
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Changes in 1.12+ and 2.2.0+ and 3.0+ change the counts if multiple elements selected (see note at the bottom of this //allinonescript.com/a/17426800/125981) – Mark Schultheiss

Often when checking if something is visible or not, you are going to go right ahead immediately and do something else with it. jQuery chaining makes this easy.

So if you have a selector and you want to perform some action on it only if is visible or hidden, you can use filter(":visible") or filter(":hidden") followed by chaining it with the action you want to take.

So instead of an if statement, like this:

if ($('#btnUpdate').is(":visible"))
{
     $('#btnUpdate').animate({ width: "toggle" });   // Hide button
}

Or more efficient, but even uglier:

var button = $('#btnUpdate');
if (button.is(":visible"))
{
     button.animate({ width: "toggle" });   // Hide button
}

You can do it all in one line:

$('#btnUpdate').filter(":visible").animate({ width: "toggle" });
19 upvote
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No reason to extract the DOM node in the snippet used in the example, and then have to look it back up again. Better to just do: var $button = $('#btnUpdate'); And then in the If expressions just use $button instead of $(button). Has the advantage of caching the jQuery object. – LocalPCGuy

From How do I determine the state of a toggled element?


You can determine whether an element is collapsed or not by using the :visible and :hidden selectors.

var isVisible = $('#myDiv').is(':visible');
var isHidden = $('#myDiv').is(':hidden');

If you're simply acting on an element based on its visibility, you can just include :visible or :hidden in the selector expression. For example:

 $('#myDiv:visible').animate({left: '+=200px'}, 'slow');
2 upvote
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wondering why no answer mentions the case when element is moved away from the visible window, like top:-1000px... Guess it's an edge-case – jazzcat

None of these answers address what I understand to be the question, which is what I was searching for, "How do I handle items that have visibility: hidden?". Neither :visible nor :hidden will handle this, as they are both looking for display per the documentation. As far as I could determine, there is no selector to handle CSS visibility. Here is how I resolved it (standard jQuery selectors, there may be a more condensed syntax):

$(".item").each(function() {
    if ($(this).css("visibility") == "hidden") {
        // handle non visible state
    } else {
        // handle visible state
    }
});
14 upvote
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This answer is good to handle visibility literally, but the question was How you would test if an element has been hidden or shown using jQuery?. Using jQuery means: the display property. – MarioDS
7 upvote
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Elements with visibility: hidden or opacity: 0 are considered to be visible, since they still consume space in the layout. See answer by Pedro Rainho and jQuery documentation on the :visible selector. – awe
8 upvote
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you need to traverse up the DOM to check the node's parents, or else ,this is useless. – vsync
3 upvote
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this won't work if you hide element with .hide(). – user3197818

This works for me, and I am using show() and hide() to make my div hidden/visible:

if( $(this).css('display') == 'none' ){
    /* your code goes here */
} else {
    /* alternate logic   */
}

The :visible selector according to the jQuery documentation:

  • They have a CSS display value of none.
  • They are form elements with type="hidden".
  • Their width and height are explicitly set to 0.
  • An ancestor element is hidden, so the element is not shown on the page.

Elements with visibility: hidden or opacity: 0 are considered to be visible, since they still consume space in the layout.

This is useful in some cases and useless in others, because if you want to check if the element is visible (display != none), ignoring the parents visibility, you will find that doing .css("display") == 'none' is not only faster, but will also return the visibility check correctly.

If you want to check visibility instead of display, you should use: .css("visibility") == "hidden".

Also take into consideration the additional jQuery notes:

Because :visible is a jQuery extension and not part of the CSS specification, queries using :visible cannot take advantage of the performance boost provided by the native DOM querySelectorAll() method. To achieve the best performance when using :visible to select elements, first select the elements using a pure CSS selector, then use .filter(":visible").

Also, if you are concerned about performance, you should check Now you see me… show/hide performance (2010-05-04). And use other methods to show and hide elements.

I would use CSS class .hide { display: none!important; }.

For hiding/showing, I call .addClass("hide")/.removeClass("hide"). For checking visibility, I use .hasClass("hide").

It's a simple and clear way to check/hide/show elements, if you don't plan to use .toggle() or .animate() methods.

8 upvote
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.hasClass('hide') doesn't check if an ancestor of the parent is hidden (which would make it hidden too). You could possibly get this to work correctly by checking if .closest('.hide').length > 0, but why reinvent the wheel? – nbrooks
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Variant you propose returns if element visible on html, my variant returns if element was directly hidden by your javascript code/view engine. If your know that parent elements should never be hidden - use .hasClass() to be more strict and prevent future bugs. If you want to check not only visibility but element state set too - use .hasClass() too. In other cases .closest() is better. – Evgeny Levin

Another answer you should put into consideration is if you are hiding an element, you should use jQuery, but instead of actually hiding it, you remove the whole element, but you copy its HTML content and the tag itself into a jQuery variable, and then all you need to do is test if there is such a tag on the screen, using the normal if (!$('#thetagname').length).

How element visibility and jQuery works;

An element could be hidden with display:none, visibility:hidden or opacity:0. The difference between those methods:

  • display:none hides the element, and it does not take up any space;
  • visibility:hidden hides the element, but it still takes up space in the layout;
  • opacity:0 hides the element as "visibility:hidden", and it still takes up space in the layout; the only difference is that opacity lets one to make an element partly transparent;

    if ($('.target').is(':hidden')) {
      $('.target').show();
    } else {
      $('.target').hide();
    }
    if ($('.target').is(':visible')) {
      $('.target').hide();
    } else {
      $('.target').show();
    }
    
    if ($('.target-visibility').css('visibility') == 'hidden') {
      $('.target-visibility').css({
        visibility: "visible",
        display: ""
      });
    } else {
      $('.target-visibility').css({
        visibility: "hidden",
        display: ""
      });
    }
    
    if ($('.target-visibility').css('opacity') == "0") {
      $('.target-visibility').css({
        opacity: "1",
        display: ""
      });
    } else {
      $('.target-visibility').css({
        opacity: "0",
        display: ""
      });
    }
    

    Useful jQuery toggle methods:

    $('.click').click(function() {
      $('.target').toggle();
    });
    
    $('.click').click(function() {
      $('.target').slideToggle();
    });
    
    $('.click').click(function() {
      $('.target').fadeToggle();
    });
    
19 upvote
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Another difference between visibility:hidden and opacity:0 is that the element will still respond to events (like clicks) with opacity:0. I learned that trick making a custom button for file uploads. – urraka
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also if you hide input with opacity:0, it still gets selected with tab key – YangombiUmpakati

One can simply use the hidden or visible attribute, like:

$('element:hidden')
$('element:visible')

Or you can simplify the same with is as follows.

$(element).is(":visible")

ebdiv should be set to style="display:none;". It is works for show and hide:

$(document).ready(function(){
    $("#eb").click(function(){
        $("#ebdiv").toggle();
    });    
});

You can also do this using plain JavaScript:

function isRendered(domObj) {
    if ((domObj.nodeType != 1) || (domObj == document.body)) {
        return true;
    }
    if (domObj.currentStyle && domObj.currentStyle["display"] != "none" && domObj.currentStyle["visibility"] != "hidden") {
        return isRendered(domObj.parentNode);
    } else if (window.getComputedStyle) {
        var cs = document.defaultView.getComputedStyle(domObj, null);
        if (cs.getPropertyValue("display") != "none" && cs.getPropertyValue("visibility") != "hidden") {
            return isRendered(domObj.parentNode);
        }
    }
    return false;
}

Notes:

  1. Works everywhere

  2. Works for nested elements

  3. Works for CSS and inline styles

  4. Doesn't require a framework

5 upvote
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Works slightly differently to jQuery's; it considers visibility: hidden to be visible. – alex
3 upvote
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It's easy enough to change the code above to mimic the (arguably stupid) jQuery behavior. . . . . function isRendered(o){if((o.nodeType!=1)||(o==document.body)){return true;}if(o.currentStyle&&o.currentStyle["display"]!="none"){‌​return isRendered(o.parentNode);}else if(window.getComputedStyle){if(document.defaultView.getCompu‌​tedStyle(o, null).getPropertyValue("display")!="none"){return isRendered(o.parentNode);}}return false;} – Matt Brock
2 upvote
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Sure, I was just adding that for the benefit of users who used this without scanning its code. :) – alex

This may work:

expect($("#message_div").css("display")).toBe("none");
6 upvote
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What language/dialect/library is this? I'm not familiar with this syntax in JS... – nbrooks
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It looks like a jasmine unit test. – Mottie

$('#clickme').click(function() {
  $('#book').toggle('slow', function() {
    // Animation complete.
    alert($('#book').is(":visible")); //<--- TRUE if Visible False if Hidden
  });
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="clickme">
  Click here
</div>
<img id="book" src="http://www.chromefusion.com/wp-content/uploads/2012/06/chrome-logo.jpg" alt="" />

Source:

Blogger Plug n Play - jQuery Tools and Widgets: How to See if Element is hidden or Visible Using jQuery

jsFiddle:

JSFiddle - ipsjolly - k4WWj

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@Adrew but this link is showing working example of this function. I think a practical answer may weight over a full page of text :) – jolly.exe
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@jolly.exe until that working example goes away that is. – Kevin B

To check if it is not visible I use !:

if ( !$('#book').is(':visible')) {
    alert('#book is not visible')
}

Or the following is also the sam, saving the jQuery selector in a variable to have better performance when you need it multiple times:

var $book = $('#book')

if(!$book.is(':visible')) {
    alert('#book is not visible')
}
upvote
  flag
How did you determined that saving a selector in variable is really faster? – Ilia Rostovtsev
3 upvote
  flag
Hi @Ilia Rostovtsev jsperf.com/caching-jquery-selectors There you can run the test. Anyways it's nice to have it cached so it can be accessed faster – Matthias Wegtun
2 upvote
  flag
This is suitable if you want to use a single variable through out the process instead of calling and calling the same object. – Kenneth Palaganas

Use class toggling, not style editing . . .

Using classes designated for "hiding" elements is easy and also one of the most efficient methods. Toggling a class 'hidden' with a Display style of 'none' will perform faster than editing that style directly. I explained some of this pretty thoroughly in Stack Overflow question Turning two elements visible/hidden in the same div.


JavaScript Best Practices and Optimization

Here is a truly enlightening video of a Google Tech Talk by Google front-end engineer Nicholas Zakas:

Example:

$(document).ready(function() {
  if ($("#checkme:hidden").length) {
    console.log('Hidden');
  }
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="checkme" class="product" style="display:none">
  <span class="itemlist"><!-- Shows Results for Fish --></span> Category:Fish
  <br>Product: Salmon Atlantic
  <br>Specie: Salmo salar
  <br>Form: Steaks
</div>

Also here's a ternary conditional expression to check the state of the element and then to toggle it:

$('someElement').on('click', function(){ $('elementToToggle').is(':visible') ? $('elementToToggle').hide('slow') : $('elementToToggle').show('slow'); });
3 upvote
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Or, y'kno, just get rid of the entire conditional and say $('elementToToggle').toggle('slow');... :) – nbrooks
if($('#postcode_div').is(':visible')) {
    if($('#postcode_text').val()=='') {
        $('#spanPost').text('\u00a0');
    } else {
        $('#spanPost').text($('#postcode_text').val());
}

You need to check both... Display as well as visibility:

if ($(this).css("display") == "none" || $(this).css("visibility") == "hidden") {
    // The element is not visible
} else {
    // The element is visible
}

If we check for $(this).is(":visible"), jQuery checks for both the things automatically.

Because Elements with visibility: hidden or opacity: 0 are considered visible, since they still consume space in the layout (as described for jQuery :visible Selector) - we can check if element is really visible in this way:

function isElementReallyHidden (el) {
    return $(el).is(":hidden") || $(el).css("visibility") == "hidden" || $(el).css('opacity') == 0;
}

var booElementReallyShowed = !isElementReallyHidden(someEl);
$(someEl).parents().each(function () {
    if (isElementReallyHidden(this)) {
        booElementReallyShowed = false;
    }
});

After all, none of examples suits me, so I wrote my own.

Tests (no support of Internet Explorer filter:alpha):

a) Check if the document is not hidden

b) Check if an element has zero width / height / opacity or display:none / visibility:hidden in inline styles

c) Check if the center (also because it is faster than testing every pixel / corner) of element is not hidden by other element (and all ancestors, example: overflow:hidden / scroll / one element over enother) or screen edges

d) Check if an element has zero width / height / opacity or display:none / visibility:hidden in computed styles (among all ancestors)

Tested on

Android 4.4 (Native browser/Chrome/Firefox), Firefox (Windows/Mac), Chrome (Windows/Mac), Opera (Windows Presto/Mac Webkit), Internet Explorer (Internet Explorer 5-11 document modes + Internet Explorer 8 on a virtual machine), Safari (Windows/Mac/iOS)

var is_visible = (function () {
    var x = window.pageXOffset ? window.pageXOffset + window.innerWidth - 1 : 0,
        y = window.pageYOffset ? window.pageYOffset + window.innerHeight - 1 : 0,
        relative = !!((!x && !y) || !document.elementFromPoint(x, y));
        function inside(child, parent) {
            while(child){
                if (child === parent) return true;
                child = child.parentNode;
            }
        return false;
    };
    return function (elem) {
        if (
            document.hidden ||
            elem.offsetWidth==0 ||
            elem.offsetHeight==0 ||
            elem.style.visibility=='hidden' ||
            elem.style.display=='none' ||
            elem.style.opacity===0
        ) return false;
        var rect = elem.getBoundingClientRect();
        if (relative) {
            if (!inside(document.elementFromPoint(rect.left + elem.offsetWidth/2, rect.top + elem.offsetHeight/2),elem)) return false;
        } else if (
            !inside(document.elementFromPoint(rect.left + elem.offsetWidth/2 + window.pageXOffset, rect.top + elem.offsetHeight/2 + window.pageYOffset), elem) ||
            (
                rect.top + elem.offsetHeight/2 < 0 ||
                rect.left + elem.offsetWidth/2 < 0 ||
                rect.bottom - elem.offsetHeight/2 > (window.innerHeight || document.documentElement.clientHeight) ||
                rect.right - elem.offsetWidth/2 > (window.innerWidth || document.documentElement.clientWidth)
            )
        ) return false;
        if (window.getComputedStyle || elem.currentStyle) {
            var el = elem,
                comp = null;
            while (el) {
                if (el === document) {break;} else if(!el.parentNode) return false;
                comp = window.getComputedStyle ? window.getComputedStyle(el, null) : el.currentStyle;
                if (comp && (comp.visibility=='hidden' || comp.display == 'none' || (typeof comp.opacity !=='undefined' && comp.opacity != 1))) return false;
                el = el.parentNode;
            }
        }
        return true;
    }
})();

How to use:

is_visible(elem) // boolean
.is(":not(':hidden')") /*if shown*/
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  flag
Because :not(':hidden') is not the same as is(':visible'). "Visible" works with css "opacity" not with JQuery "show()/hide()". Plus, there is no extra quotation. Every set plays a role in this little code. – Kareem
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  flag
1) both :visible and :hidden check CSS element and ancestor visibility and not just the display: none as you now suggest. 2) quotes inside a pseudo-selector are not required if the selector contains only : and alphanumerics (e.g. :not(:hidden) is the same as not(':hidden') (only a little faster) and 3) how will you become better if you cannot accept that you may actually be incorrect sometimes? :) – Gone Coding

When testing an element against :hidden selector in jQuery it should be considered that an absolute positioned element may be recognized as hidden although their child elements are visible.

This seems somewhat counter-intuitive in the first place – though having a closer look at the jQuery documentation gives the relevant information:

Elements can be considered hidden for several reasons: [...] Their width and height are explicitly set to 0. [...]

So this actually makes sense in regards to the box-model and the computed style for the element. Even if width and height are not set explicitly to 0 they may be set implicitly.

Have a look at the following example:

console.log($('.foo').is(':hidden')); // true
console.log($('.bar').is(':hidden')); // false
.foo {
  position: absolute;
  left: 10px;
  top: 10px;
  background: #ff0000;
}

.bar {
  position: absolute;
  left: 10px;
  top: 10px;
  width: 20px;
  height: 20px;
  background: #0000ff;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="foo">
  <div class="bar"></div>
</div>


UPDATE FOR JQUERY 3.x:

With jQuery 3 the described behavior will change! Elements will be considered visible if they have any layout boxes, including those of zero width and/or height.

JSFiddle with jQuery 3.0.0-alpha1:

http://jsfiddle.net/pM2q3/7/

The same JS will then have this output:

console.log($('.foo').is(':hidden')); // false
console.log($('.bar').is(':hidden')); // false

Simply check visibility by checking for a boolean value, like:

if (this.hidden === false) {
    // Your code
}

I used this code for each function. Otherwise you can use is(':visible') for checking the visibility of an element.

But what if the element's CSS is like the following?

.element{
    position: absolute;left:-9999;    
}

So this answer to Stack Overflow question How to check if an element is off-screen should also be considered.

A function can be created in order to check for visibility/display attributes in order to gauge whether the element is shown in the UI or not.

function checkUIElementVisible(element) {
    return ((element.css('display') !== 'none') && (element.css('visibility') !== 'hidden'));
}

Working Fiddle

Maybe you can do something like this

$(document).ready(function() {
   var visible = $('#tElement').is(':visible');

   if(visible) {
      alert("visible");
                    // Code
   }
   else
   {
      alert("hidden");
   }
});
<script src="https://code.jquery.com/jquery-1.10.2.js"></script>

<input type="text" id="tElement" style="display:block;">Firstname</input>

Example of using the visible check for adblocker is activated:

$(document).ready(function(){
  if(!$("#ablockercheck").is(":visible"))
    $("#ablockermsg").text("Please disable adblocker.").show();
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="ad-placement" id="ablockercheck"></div>
<div id="ablockermsg" style="display: none"></div>

"ablockercheck" is a ID which adblocker blocks. So checking it if it is visible you are able to detect if adblocker is turned On.

if($('#id_element').is(":visible")){
   alert('shown');
}else{
   alert('hidden');
}

This is some option to check that tag is visible or not

 // using a pure CSS selector  
   if ($('p:visible')) {  
      alert('Paragraphs are visible (checked using a CSS selector) !');  
   };  
  
   // using jQuery's is() method  
   if ($('p').is(':visible')) {  
      alert('Paragraphs are visible (checked using is() method)!');  
   };  
  
   // using jQuery's filter() method  
   if ($('p').filter(':visible')) {  
      alert('Paragraphs are visible (checked using filter() method)!');  
   };  
  
   // you can use :hidden instead of :visible to reverse the logic and check if an element is hidden  
   // if ($('p:hidden')) {  
   //    do something  
   // };  

if($("h1").is(":hidden")){
    // your code..
}

You can just add a class when it is visible. Add a class, show. Then check for it have a class:

$('#elementId').hasClass('show');

It returns true if you have the show class.

Add CSS like this:

.show{ display: block; }

This is how jQuery internally solves this problem:

jQuery.expr.pseudos.visible = function( elem ) {
    return !!( elem.offsetWidth || elem.offsetHeight || elem.getClientRects().length );
};

If you don't use jQuery, you can just leverage this code and turn it into your own function:

function isVisible(elem) {
    return !!( elem.offsetWidth || elem.offsetHeight || elem.getClientRects().length );
};

Which isVisible will return true as long as the element is visible.

You can use this:

$(element).is(':visible');

Example code

$(document).ready(function()
{
    $("#toggle").click(function()
    {
        $("#content").toggle();
    });

    $("#visiblity").click(function()
    {
       if( $('#content').is(':visible') )
       {
          alert("visible"); // Put your code for visibility
       }
       else
       {
          alert("hidden");
       }
    });
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.2/jquery.min.js"></script>

<p id="content">This is a Content</p>

<button id="toggle">Toggle Content Visibility</button>
<button id="visibility">Check Visibility</button>

I searched for this, and none of the answers are correct for my case, so I've created a function that will return false if one's eyes can't see the element

jQuery.fn.extend({
  isvisible: function() {
    //
    //  This function call this: $("div").isvisible()
    //  Return true if the element is visible
    //  Return false if the element is not visible for our eyes
    //
    if ( $(this).css('display') == 'none' ){
        console.log("this = " + "display:none");
        return false;
    }
    else if( $(this).css('visibility') == 'hidden' ){
        console.log("this = " + "visibility:hidden");   
        return false;
    }
    else if( $(this).css('opacity') == '0' ){
        console.log("this = " + "opacity:0");
        return false;
    }   
    else{
        console.log("this = " + "Is Visible");
        return true;
    }
  }  
});
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Just a note, if the selector returns an empty set of items, this method will return true, so check length first if you looking for invisible items : var items = jQuery('.selector'); if (items.length == 0 || !items.isVisible()) { alert('item is not visible'); } – Nnoel

As hide(), show() and toggle() attaches inline css (display:none or display:block) to element. Similarly, we can easily use ternary operator to check weather element is hidden or visible by checking display css.

var visible = $('#element').css('display') === 'block'? true:false;

This will easily check whether the element is visible or not.

You can use the

$( "div:visible" ).click(function() {
  $( this ).css( "background", "yellow" );
});
$( "button" ).click(function() {
  $( "div:hidden" ).show( "fast" );
});

API Documentation: https://api.jquery.com/visible-selector/

I just want to clarify that, in jQuery,

Elements can be considered hidden for several reasons:

  • They have a CSS display value of none.
  • They are form elements with type="hidden".
  • Their width and height are explicitly set to 0.
  • An ancestor element is hidden, so the element is not shown on the page.

Elements with visibility: hidden or opacity: 0 are considered to be visible, since they still consume space in the layout. During animations that hide an element, the element is considered to be visible until the end of the animation.

Source: :hidden Selector | jQuery API Documentation

if($('.element').is(':hidden')) {
  // Do something
}

There are quite a few ways to check if an element is visible or hidden in jQuery.

Demo HTML for example reference

<div id="content">Content</div>
<div id="content2" style="display:none">Content2</div>

Use Visibility Filter Selector $('element:hidden') or $('element:visible')

  • $('element:hidden'): Selects all elements that are hidden.

    Example:
       $('#content2:hidden').show();
    
  • $('element:visible'): Selects all elements that are visible.

    Example:
       $('#content:visible').css('color', '#EEE');
    

Read more at http://api.jquery.com/category/selectors/visibility-filter-selectors/

Use is() Filtering

    Example:
       $('#content').is(":visible").css('color', '#EEE');

    Or checking condition
    if ($('#content').is(":visible")) {
         // Perform action
    }

Read more at http://api.jquery.com/is/

There are too many methods to check for hidden elements. This is the best choice (I just recommended you):

Using jQuery, make an element, "display:none", in CSS for hidden.

The point is:

$('element:visible')

And an example for use:

$('element:visible').show();

To be fair the question pre-dates this answer. I add it not to criticise the OP but to help anyone still asking this question.

The correct way to determine whether something is visible is to consult your view-model. If you don't know what that means then you are about to embark on a journey of discovery that will make your work a great deal less difficult.

Here's an overview of the model-view-viewmodel architecture (MVVM).

KnockoutJS is a binding library that will let you try this stuff out without learning an entire framework.

And here's some JS and a DIV that may or may not be visible.

<html><body>
<script src="https://cdnjs.cloudflare.com/ajax/libs/knockout/3.4.1/knockout-min.js"></script>
<script>
var vm = {
  IsDivVisible: ko.observable(true);
}
vm.toggle = function(data, event) {
  //get current visibility state for the div
  var x = IsDivVisible();
  //set it to the opposite
  IsDivVisible(!x);
}
ko.applyBinding(vm);
</script>
<div data-bind="visible: IsDivVisible">Peekaboo!</div>
<button data-bind="click: toggle">Toggle the div's visibility</button>
</body></html>

Notice that the toggle function does not consult the DOM to determine the visibility of the div, it consults the view-model.

$('someElement').on('click', function(){ $('elementToToggle').is(':visible')

Just simply check if that element is visible and it will return a boolean, jQuery hide the elements by adding display none to the element, so if you want to use pure JavaScript, you can still do that, for example:

if (document.getElementById("element").style.display === 'block') { 
  // your element is visible, do whatever you'd like
}

Also, you can use jQuery as seems the rest of your code using that and you have smaller block of code, something like below in jQuery, do the same track for you:

if ($(element).is(":visible")) { 
    // your element is visible, do whatever you'd like
};

Also using css method in jQuery can result the same thing:

if ($(element).css('display')==='block') {
    // your element is visible, do whatever you'd like
}

Also in case of checking for visibility and display, you can do the below:

if ($(this).css("display")==="block"||$(this).css("visibility")==="visible") {
   // your element is visible, do whatever you'd like
}

Very simple:

if($('#div').is(":visible")) {
    // visible
} else {
    // hide
}

Simply check for the display attribute (or visibility depending on what kind of invisibility you prefer). Example :

if ($('#invisible').css('display') == 'none') {
    // This means the HTML element with ID 'invisible' has its 'display' attribute set to 'none'
}

You can use a css class when it visible or hidden by toggling the class.

.show{ display :block; }

Set your jQuery toggleClass() or addClass() or removeClass();.

As an example,

jQuery('#myID').toggleClass('show')

The above code will add show css class when the element don't have show and will remove when it has show class.

And when you are checking if it visible or not, You can follow this jQuery code,

jQuery('#myID').hasClass('show');

Above code will return a boolean (true) when #myID element has our class (show) and false when it don't have the (show) class.

You can use below code for check div is visible or not.

if($('#postcode_div').is(':visible')) {
      //put your code if div is visible.
    } else {
     //put your code if div is not visible.
}

You can do this:

isHidden = function(element){
    return (element.style.display === "none");
};

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